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An object falling through a static water...

An object falling through a static water column is observed to have an acceleration given by the relation ang-bu where g is acceleration due to gravity and 'b' is a constant. After sufficiently long time of its release, it is observed to fall with a constant speed. What must be the value of its constant speed ?

A

v=g/b

B

v=a/b

C

v=g`xx`b

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
a

Acceleration a=g-bv
After a long intervel the viscous restisance become constant and body begins to fall with a consatnt speed. As at that moment a=0
`:.` 0=g-b.v
`:.` bv=g or v=g//b
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