A point mass initially at rest moves along x-axis. Its acceleration varies with time as a = 6t+ 5 ms. If it starts from origin, the distance covered by it in 1 s is

Options

A. 3 m
B. 5.5 m
C. 3.5 m
D. 4 m

Answer

c

Explanation

Here acceleration =6t+5
`(dv)/(dt)=6t+5`
or dv=(6t+5) dt, Intergrating
`v=(6t^(2))/(2)+5t=3t^(2)+5t`
`ds(3t^(2)+5t)dt`
`s=(3t^(3))/(3)+(5t^(2))/(2)`
`(s)_(t)=(3xx1xx1)/(3)+(5)/(2)1xx1=3.5`