A pole is held vertically with one end on the ground. The length of the pole is 30 m. The pole is allowed to fall. Assuming that the lower end of the pole does not slip with what velocity will the upper end strike the ground g = 10 m

Options

A. 5 m `s^(-1)`
B. 10 `s^(-1)`
C. 20 `s^(-1)`
D. 30 `s^(-1)`

Answer

d

Explanation

`1/2 Iomega^(2)=mgh` (conservation of energy)
`(1)/(2) (ml^2)/(3)xx(v/I)^(2)=mgxx(l)/(2)`
`:. V=sqrt(3gl)`
`=sqrt(3xx10xx30)=30 ms^(-1)`