The distance time graph of a particle at time t makes an angle of `45^(@)` with time axis. After 1 second it makes an angle of `60^(@)` with time axis, what is the acceleration of the particle ?

Options

A. `sqrt(3-1)`
B. `sqrt(3+1)`
C. `sqrt(3)`
D. 1

Answer

a

Explanation

Velocity is given by the slope of s-t graph initial velcotiy =u tan`45^(@)=1`,
Velocity after one sec=v=`tan60^(@)=sqrt(3)`
`:. a=(v-u)/(t)=(sqrt(3-1))/(1)=(sqrt(3-1))`.