A bus starts moving with an acceleration2 ms? A cyclist 96 m behind the bus starts simultaneously towards the bus at 20 m s-, after what time will he able to overtake the bus?

Options

A. 4 s
B. 8 s
C. 12 s
D. 16 s

Answer

b

Explanation

Here `96+(1)/(2)rt^(2)`=Total distance to be covered by the cyclist.
Also total distance covered by the cylist =20.t
`:. 20.t=(1)/(2)xx2t^(2)+96`
or `t^(2)-20t+96`
`t=(20pmsqrt(400-384))/(2)`
`t=(20pm4)/(2)=12sec,8sec`
Minimum time =8 sec