A man is at a distance from the bus: when the bus begins to move with a constant acceleration 'a', with what minimum velocity the man should run towards the bus so as to catch it?

Options

A. `sqrt(2ax)`
B. 2ax
C. `sqrt(ax)`
D. ax

Answer

a

Explanation

Here `x+(1)/(2)at^(2)` =Distance to be covered.
Distance covered by the man=vt
`:. X+(1)/(2)at^(2)-vt+x=0`
or `t=(vpmsqrt(v^2-2ax))/(a)`
Now t is real when `sqrt(v^(2)-2ax)` is +ve and its minimum value is Zero.
`:. V^2-2ax=0` or `v=sqrt(2ax)`