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The x and y co-ordinates of a particle a...

The x and y co-ordinates of a particle at any instant are `x = 4t^2` + 7t and y = 5t where x, y are in metres and in seconds. The acceleration at t=5s is :

A

Zero

B

20 `m s^(-2)`

C

8 `m s^(-2)`

D

40 `m s^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
c
Here a=`sqrt(a_(x)^(2)+a_(y)^(2))` But `a_(y)=0`
`( :.(d^2y)/(dt^(2))=0)` and `a=a_(x)=(d^(2)x)/(dt^(2))=8 m s^(-2)`
For any value of .t.
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