Two bodies begin a free fall from the same height at a time interval of Ns. If vertical separation between the two bodies is 1 after second from the start of the first body, then is equal to :

Options

A. `sqrt(nN)`
B. `(1)/(gN)`
C. `(1)/(gN)+(N)/(2)`
D. `(1)/(gN)-(N)/(4)`

Answer

c

Explanation

Here `S_(1)=(1)/(2)gn^(2)` and `S_2=(g)/(2)(n-N)^(2)`
`S_1-S_2=(1)/(2)g[n^(2)-(n-N)^(2)]`
`1=(g)/(2)(2n-N)(N)`
`2n(2)/(gN)+N` and `n=(1)/(gN)+(N)/(2)`