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The velocity of particle is v=v0 +gt+ft^...

The velocity of particle is v=`v_0` +gt+`ft^(2)` if its position is x =0 at t=0, then its displacement after unit time is:

A

`v_0 +g//2+f//3`

B

`v_0` +g+f

C

`v_0`+g/2+f

D

`v_0` +2g+3f

Text Solution

Verified by Experts

The correct Answer is:
a

Here `v=v_0`+gt+`ft^(2)`
or `(dx)/(dt)=v_0`+gt+`ft^(2)`
`dx=v_0dt`+ gt dt+`ft^2` dt
`int_(0)^(x) dx=v_(0)int_(0)^(1)dt+gin_(0)^(1)t dt +f int_(0)^(1) t^(2) dt`
`=v_0 +(g)/(2)+(f)/(3)`
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