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A person throws balls into air verticall...

A person throws balls into air vertically upward in regular intervals of time of one second . The next ball is thrown when the velocity of the ball thrown earlier becomes zero . The height to which the balls rise is …
(Assume , g = `10 ms^(-2)`)

A

5 m

B

10 m

C

7.5m

D

20m

Text Solution

Verified by Experts

The correct Answer is:
a
Sice the ball are thrown after a gap of 1S. So 1s is time of ascent of first ball.
`:.` time of descent is also 1s
`:. H=(1)/(2)g t^(2)`
`=(1)/(2)xx10xx1^(2)=5m`
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