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A body of mass 'm' is travelling with a ...

A body of mass 'm' is travelling with a velocity 'u' . When a constant retarding force 'F' is applied , it comes to rest after travelling a distance `s_1` . If the initial velocity is 2u , with the same force F , the distance travelled before it comes to rest is `s_(2)` . then

A

`s_2=2s_1`

B

`s_2=(s_1)/(2)`

C

`s_2=s_1`

D

`s_2 =4s_1`

Text Solution

Verified by Experts

The correct Answer is:
d
When the velocity of the body become doubled the disatnce required to stop the body by same retarding force become 4 times.
`:.S_2=4S_1`
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