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A stone is thrown vertically at a speed ...

A stone is thrown vertically at a speed of `30 ms^(-1)` taking an angle of `45^(@)` with the horizontal. What is the maximum height reached by the stone ? Take `g = 10 ms^(-2)`.

A

30 m

B

22.5 m

C

15 m

D

10 m

Text Solution

Verified by Experts

The correct Answer is:
b
`H=(u^2 sin^2theta)/(2g)`
`H=((30)^(2) sin^2 45^(@))/(2xx10)=(900xx(1)/(2))/(20)==22.5 m`
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