Home
Class 12
PHYSICS
A stone of mass 0.005 kg is thrown verti...

A stone of mass 0.005 kg is thrown vertically upwards. What is the direction and magnitude of net force on the stone during its upward motion ?

A

0.049 N vertically downwards

B

9.8 N vertically downwards

C

0.49 N vertically upwards

D

0.98 N vertically downwards.

Text Solution

Verified by Experts

The correct Answer is:
a
When the stone is thrown vertically upward then net force on the stone is F=mg actiing vertically downwards
`:. F=0.005xx9.8=0.49 N` vertically downwards.
Promotional Banner

Topper's Solved these Questions

  • DESCRIPTION OF MOTION IN ONE DIMENSION

    MODERN PUBLICATION|Exercise Revision Test|45 Videos

  • DESCRIPTION OF MOTION IN ONE DIMENSION

    MODERN PUBLICATION|Exercise MULTIPLE CHOICE QUESTION (LEVEL-II)|54 Videos

  • CURRENT ELECTRICITY

    MODERN PUBLICATION|Exercise RECENT COMPETITIVE QUESTIONS|32 Videos

  • DESCRIPTION OF MOTION IN TWO AND THREE DIMENSION

    MODERN PUBLICATION|Exercise Revision TEST|36 Videos

Similar Questions

Explore conceptually related problems

A stone of mass 0.05 kg is thrown vertically upwards. What is the direction and magnitude of net force on the stone during its upward motion?

A particle of mass 100 g is thrown vertically upwards with a speed of 5 m/s. The work done by the force of gravity during the time the particle goes up is:

A stone is thrown in a vertically upward direction with a velocity of 5m/s. If the acceleration of the stone during its motion is 10 m//s^(2) in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?

A body is projected vertically up. What is the distance covered in its last second of upward motion? (g=10 m//s^(2))

A player throws a ball vertically upwards. What is the direction of acceleration during upward motion? What is the velocity at the highest point of its motion.

A body of mass 1 kg is thrown vertically upwards with initial K.E. of 98 joule. The height at which its energy is reduced to half will be

A ball of mass 0-2 kg is thrown vertically upwards by applying a force by hand. If the hand moves 0.2 m while applying the force and the ball goes upto 2 m height further, find the magnitude of the force. Consider g = 10 m//s^(2) :