A bomb of mass 9 kg explodes into two pieces of mass 3 kg and 6 kg. The velocity of mass 3 kg is `16 ms^( -1)` The K.E. of mass 6 kg is:

Options

A. 96 joules
B. 192 joules
C. 384 joules
D. 768 jules

Answer

b

Explanation

`Mu=m_(1)upsilon_(1)+m_(2)upsilon_(2)implies0=3xx16+6.upsilon_(2)`
`impliesupsilon_(2)=-8m//s`
`:.K.E.=(1)/(2)m_(2)upsilon_(2)^(2)=(1)/(2)6xx64=192J`
Hence correct choice is (b).