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A bullet of mass a moving with velocity ...

A bullet of mass a moving with velocity b strikes a large stationary block of wood of mass c, and remains embed in it, the final velocity of the system is :

A

`(b)/(c+b)`

B

`(a+b)/(c)a`

C

`(a)/(a+c)b`

D

`(a+b)/(a)b`

Text Solution

Verified by Experts

The correct Answer is:
c
By conservation of momentum
`m_(1)u-(1)+m_(2)u_(2)=(m_(1)+m_(2))V`
`:.ab+cxx0=(a+c)Vimplies(ab)/(a+c)`
Hence correct choice is (c)
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Knowledge Check

  • A bullet of mass 'm' moving with velocity *v' strikes a block of mass 'M' at rest and gets embeded into it. The K.E. of composite block will be:

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