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A particle of mass m strikes a wall norm...

A particle of mass m strikes a wall normally with a velocity v and then its velocity reversed. The change in momentum is :

A

m`upsilon`

B

2m`upsilon`

C

zero

D

- 2m`upsilon`

Text Solution

Verified by Experts

The correct Answer is:
d
`Deltap=vecp_(2)-p_(1)=-vec(m upsilon)-vec((m upsilon))=-2vec((m upsilon))`
Hence correct choice is (d).
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