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A car is moving along a straight horizon...

A car is moving along a straight horizontal road with a speed V. If the coefficient of friction between road and tyres is H, the shortest distance in which the car stops when engine is shut off, is :

A

`(V^(2))/(2mug)`

B

`(V)/(mug)`

C

`(V)/(mu)`

D

`(V^(4))/(mu^(2)g^(2))`

Text Solution

Verified by Experts

The correct Answer is:
a

K.E. of Car = Work done against friction
`(1)/(2)mV^(2)=mumgxxX`
`:.x=(V^(2))/(2mug)`
Hence corect choice is (a).
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