A cricket ball of mass 0-5 kg strikes a bat normally with a velocity of `30 ms^(-1)` and rebounds with a velocity of `20 ms^(-1)` in the opposite direction. The impulse of the force exerted by the ball on the bat is :

Options

A. `0.5 Ns`
B. 25 Ns
C. 50 NS
D. 1.0 Ns

Answer

b

Explanation

I = [Change in momentum] = `mv - (- m upsilon’)`
`= m(upsilon +upsilon’) = 0.5 (30 + 20) = 25 Ns`
Hence correct choice is (b)