A car moving at a speed V is stopped by a retarding force F in a distance S. If the retarding force were 6F, the car will be stopped in a distance :

Options

A. `(S)/(12)`
B. `a=(1)/(3)g`
C. `(S)/(6)`
D. `(S)/(3)`

Answer

c

Explanation

Work done = change is K.E.
`F.S. =(1)/(2) m upsilon^(2)`
`S=(m upsilon^(2))/(2F)`For constant m and `upsilon`
`Sprop(1)/(F)`
When force becomes 6 times then distance `(1)/(6)th`
Hence correct choice is (c).