When forces `F_(1), F_(2), F_(3)` are acting on a particle of mass m such that F, and Fy are mutually perpendicular, then the particle remains stationary. If the force F, is now removed then the acceleration of the particle is :

Options

A. `F_(1)//m`
B. `F_(2)F_(3)//mF_(1)`
C. `(F_(2)-F_(3))//m`
D. `F_(2)//m`

Answer

a

Explanation

For the equilibrium of the body `F_(1)` must act opposite to `F_(2)` and `F_(3)` and must be equal and opposite to the resultant of `F_(2)` and `F_(3)` as shown

Thus `F_(1)=F =ma`  or `a=(F)/(m)=(F_(1))/(m)`
Hence choice is (a).