A ball whose kinetic energy is E is projected at an angle of `45^(@)` to the horizontal. The kinetic energy of the ball at the highest point of its flight willbe:

Options

A. E
B. `Esqrt(2)`
C. `E//2`
D. zero

Answer

c

Explanation

At the highest point of trajectory velocity` =upsilon cos theta`
K.E. at the throw `=(1)/(2)m upsilon^(2)cos^(2) 45^(@)`
K.E. at the highest point = `(1)/(2)mupsilon^(2)cos^(2)45^(@)`
`Exx((1)/(sqrt2))^(2)=(E)/(2)`
Hence choice is (c)