A mass of M kg is suspended by a weightless string. The horizontal force that is required to displace it until the string makes an angle of `45^(@)` with the initial vertical direction is :

Options

A. `Mg(sqrt2+1)`
B. Mg
C. `(Mg)/sqrt2`
D. `Mg(sqrt2-1)`

Answer

b

Explanation

In equilibrium
`T sin 45^(@) = F`

`T cos 45^(@)=mg`
`:.tan 45^(@)=(F)/(mg)`
`impliesF=mg`
Here choice is (b)