The velocity of a body of mass 2 kg is given by`vecupsilon=(2t overset(wedge)(i)+t^(2)overset(wedge)(j))`Find the momentum of the body after 2 seconds.

Options

A. `(8overset(wedge)(i)+8overset(wedge)(j))kg ms^(-1)`
B. `(4overset(wedge)(i)+4overset(wedge)(j))kg ms^(-1)`
C. `(6overset(wedge)(i)+6overset(wedge)(j))kg ms^(-1)`
D. `(10overset(wedge)(i)+10overset(wedge)(j))kg ms^(-1)`

Answer

a

Explanation

Here mass of the body = 2kg
`vecupsilon=(2thati+t^(2)hatj)`
velocity after 2 sec `vecupsilon`= `vecupsilon_(t)=(2xx2hati+4hatj)`
`(4hati+4hatj)`
Monentum`vecp_(t)=m vecupsilon_(t)`
`=2(4hati+4hatj)`Hence (a) is the choice.