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When a U^(238) nucleus originally at res...

When a `U^(238)` nucleus originally at rest, decays by emitting an alpha particle having speed 'u' the recoiled speed of residual nucleus is:

A

`(-4u)/(238)`

B

`(4u)/(238)`

C

`(-4u)/(234)`

D

`(4u)/(234)`

Text Solution

Verified by Experts

The correct Answer is:
c

The velocity of recoil is `upsilon=-(m)/(M).u`
`=-(4)/(234)xxu=(-4u)/(234)`
Hence choice is (c).
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