Three particles of masses 2 kg, 4 kg and 6 kg are located at the vertices of an equilateral triangle of side 0.5 m. What is the position of centre of mass if the origin is located at 2 kg mass and 4 kg mass located along x-axis ?

Options

A. 0.29 m, 0.22 m
B. 2.9 m, 2.2 m
C. 1.9 m, 1.2 m
D. None of these

Answer

A

Explanation

Here `x_(1)=0,x_(2)=0.5m,x_(3)=0.25m(0.5cos60^(@))`
`vecx=(2xx0+4xx0.5+6xx0.25)/(12)`
= 0.29 m
Also `y_(1)=y_(2)=0,y_(3)=0.5sin60^(@)=0.433m`
`vecy=(2xx0+4xx0+6xx0.433)/(12)=0.22m`