Four particles of masses 1 kg, 2 kg, 3 kg and 4 kg are at the vertices of a rectangle of sides a and b with `agtb`. If a = 1 m, b = 2 m, what is the location of their centre of mass ?

Options

A. 0.5 m, 1.4 m
B. 1.4 m, 0.5 m
C. 0.14 m, 0.05 m
D. 0.05 m, 0.14 m

Answer

A

Explanation

Here `vecx=(Sigmam_(1)x_(1))/(M)`
`=(1)/(10)(0xx1+2xxa+3xxa+4xx0)=0.5m`
`vecy=(Sigmam_(1)x_(1))/(M)`
`=(1)/(10)(0xx1+2xx0+3xxb+4xxb)`
= 1.4 m