When a sphere of moment of inertia I moves down an inclined plane, the percentage of energy which is rotational, is approximately :

Options

A. `28%`
B. `72%`
C. `100%`
D. None of these

Answer

A

Explanation

Here
Total energy `=(1)/(2)mv^(2)+(1)/(2)Iomega^(2)`
`=(1)/(2)mv^(2)+(1)/(2)xx(2)/(5)mr^(2)omega^(2)`
`=(7)/(10)mv^(2)`
`therefore %` which is rotational = `((1)/(5)m^(2)v^(2))/(7//10mv^(2))`
`=(2)/(7)xx100=28%`