A thin uniform rod of length 2l is acted upon a constant torque. The angular velocity changes from zero to `omega` in time t. The value of torque is :

Options

A. `(ml^(2)omega)/(3t)`
B. `(2ml^(2)omega)/(t)`
C. `(ml^(2)omega)/(t)`
D. `(ml^(2)omega)/(12t)`

Answer

A

Explanation

Here
`tau=(m)/(12)xx(2l)^(2)xx(omega)/(t)=(ml^(2)omega)/(3t)(because vectau=Ialpha)`