Two fly wheels A and B are mounted side by side with frictionless bearing on a common shaft. Their moments of inertia about the shaft are 5.0 kg `m^(2)` and 20.0 kg `m^(2)` respectively. Wheel A is made to rotate at 10 revolution per second. Wheel B, initially stationary is now coupled to A with the help of a clutch. The rotation speed of the wheels will become

Options

A. `2sqrt(5)` rps
B. 0.5 rps
C. 2 rps
D. None of these

Answer

C

Explanation

Here applying law of conservation of angular momentum ,
`5xx10+20xx0=(5+20)omega`
`therefore omega=(50)/(25)=2r.p.s`