A solid sphere is resting on a smooth horizontal surface. A horizontal impulse I is applied at a height 'h' from the centre so that the sphere begins to rotate just after the application of the impulse. What is ratio h/R?

Options

A. `(1)/(2)`
B. `2//5`
C. `(1)/(4)`
D. `(1)/(5)`

Answer

B

Explanation

Here Impulse = mvh
If I = M.I, then `L=Iomega`
`therefore mvh=Iomega`
or `mvh=(2)/(5)MR^(2).(v)/(R)`
`h=(2)/(5)R`
or `(h)/(R)=2//5`