Two blocks of masses 10 kg and 4 kg are connected by a negligible mass and placed on a frictionless horizontal surface. An impulse gives a velocity of 14 m/s to the heavier block in the direction of the lighter block. The velocity of the centre of mass is :

Options

A. 30 m/s
B. 20 m/s
C. 10 m/s
D. 5 m/s

Answer

C

Explanation

The velocity of C.M. is given by

`v_(C.M.)=(m_(1)v_(1)+m_(2)v_(2))/(m_(1)+m_(2))=(10xx14+4xx0)/(10+4)=10ms^(-1)`