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A thin circular ring of mass m and r is ...

A thin circular ring of mass m and r is rotating about its axis with a constant angular velocity `omega`. Two objects, each of mass m are attached gently to the opposite ends of a diameter of the ring wheel now rotates with an angular velocity :

A

`(omega(m+2M))/(m)`

B

`(omega(m-2M))/((m+2M))`

C

`(omegam)/((m+M))`

D

`(omegam)/((m+2M))`

Text Solution

Verified by Experts

The correct Answer is:
D

Angular momentum is conserved `I_(1)omega_(1)=I_(2)omega_(2)`
`mR^(2)omega=mR^(2)omega_(2)+2MR^(2)omega_(2)`
`omega_(2)=(momega)/(m+2M)`
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