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A hoop of radius r and mass m rotating w...

A hoop of radius r and mass m rotating with an angular velocity `omega_(0)` is placed on a rough horizontal surface. The initial velocity of the centre of the hoop is zero. What will be the velocity of the centre of the loop when it ceases to slip?

A

`(romega_(0))/(3)`

B

`(romega_(0))/(2)`

C

`romega_(0)`

D

`(romega_(0))/(4)`

Text Solution

Verified by Experts

The correct Answer is:
B
From conservation of angular momentum about any fix point on the surface `mr^(2)omega_(0)=2mr^(2)omega`
`therefore omega=(omega_(0))/(2)`
`therefore V_(CM)=(omega_(0)r)/(2)`
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