A man falls 50 m distance in one minute near the earth's surface, how much distance would he cover in one minute near the moon's surface? `(g_(m)=(g_(e ))/(6))`

Options

A. `50xx6m`
B. `50 m`
C. `(50)/(6)m`
D. `50xx50`m.

Answer

C

Explanation

Since `h=(1)/(2) g t^(2)`
`therefore ` on earth `50=(1)/(2) g_(e )*(60)^(2) ….(i)`
and on moon `h=(1)/(2) g_(m) (60)^(2)" " …(ii)`
Dividing (ii) by (i)
`therefore (h)/(50)=(g_(m))/(g_(e )) rArr h=50xx(1)/(6)=(50)/(6)m`
So correct choice is (c ).