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If R is the radius of the earth and g th...

If R is the radius of the earth and g the acceleration due to gravity on the earth's surface, the mean density of the earth is:

A

`(4pi G)/(3gR)`

B

`(pi Rg)/(12G)`

C

`(3g)/(4pi RG)`

D

`(3pi R)/(4gG)`

Text Solution

Verified by Experts

The correct Answer is:
C
`g=(GM)/(R^(2))=(G)/(R^(2))xx(4)/(3)pi R^(3)rho`
`therefore rho=(3g)/(4pi RG)`
So correct choice is (c ).
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