The height at which the weight of a body becomes `1//16^(th)`, its weight on the surface of earth (radius R), is:

Options

A. 4 R
B. 5 R
C. 15 R
D. 3 R

Answer

D

Explanation

`(W_(2))/(W_(1))=(mg_(2))/(mg_(1))=(g_(2))/(g_(1))=(R^(2))/((R+R)^(2))`
`(1)/(16)=(R^(2))/((R+R)^(2)) rArr (1)/(4)=(R )/(R+h)`
`R+h=4R`
`h=3R`.
Thus correct choice is (d).