A body is thrown up with a velocity `10%` more than the escape velocity `v_(e )`. When the body escapes the gravitational pull of the earth the velocity still left in the body is :

Options

A. `0.1v_(e )`
B. `0.229 v_(e )`
C. `0.458 v_(e )`
D. `0.20 v_(e )` .

Answer

C

Explanation

`v=v_(e )+(10)/(100)v_(e )=(11)/(10)v_(e )`
`therefore` Velocity of body after escaping the gravitational field is
`v=sqrt(x^(2)-1) " " v_(e )=sqrt(((121)/(100)-1))-v_(e )=sqrt((21)/(100))v_(e )`
`=0.458 v_(e )`
So correct choice is (c ).