A satellite orbiting around earth of radius R is shifted to an orbit of radius 2R. How many times the time taken for one revolution increase?

Options

A. `2*5` times
B. 2 times
C. `2*8` times
D. 8 times.

Answer

C

Explanation

According to Kepler.s 3rd law
`T^(2)prop r^(3) therefore (T_(2))/(T_(1))=((r_(2))/(r_(1)))^(3//2)`
`T_(2)=T((2R)/(R ))^(3//2)`
`rArr T_(2)=2sqrt(2)T=2xx1.41T=2.82T`
Thus correct choice is (c ).