A geostatationary satellite is orbiting the earth at a height of 5R above the surface of the earth, R being the radius of the earth. The time peiod of another satellite in hours at a height of 2R from the surface of the earth is :

Options

A. `(6)/(sqrt(2))`
B. 5
C. 10
D. `6sqrt(2)`

Answer

D

Explanation

`(T_(2))/(T_(1))=((r_(2))/(r_(1)))^(3//2)=((3R)/(6R))^(3//2)=((1)/(2))^(3//2)`
`=(1)/(2sqrt(2))`
`therefore T_(2)=(1)/(2sqrt(2))xx24=6sqrt(2)`
Thus correct choice is (d).