A satellite of mass m revolves around the earth of radius R at a height x from its surface. If g is the acceleration due to gravity on the surface of the earth, the orbital speed of the satellite is:

Options

A. `gX`
B. `((gR^(2))/(R+X))^(1//2)`
C. `(gR^(2))/(R+X)`
D. `(gR)/(R-X)`

Answer

B

Explanation

`v_(0)=sqrt((GM)/(R+x))=sqrt((gR^(2))/(R+x))`
Thus correct choice is (b).