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What is a period of revolution of earth ...

What is a period of revolution of earth satellite ? Ignore the height of satellite above the surface of earth.
Given :
The value of gravitational acceleration `g= 10 m s^(-2)`
Radius of earta `R_(E)= 6400 km`. Take `pi=3.14`.

A

85 min

B

156 min

C

83.73 min

D

90 min.

Text Solution

Verified by Experts

The correct Answer is:
C
`T=2pi sqrt((GM)/(R+h))`
Since h is negligible and `GM=gR^(2)`
`therefore T=2pi sqrt((gR^(2))/(R ))=2pi sqrt((R )/(g))`
`T=2xx(22)/(7)xx sqrt((6.4xx10^(6))/(9.8))`
`T=83.73` min
So correct choice is (c ).
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