The kinetic energy and potential energy of a particle executing simple harmonic motion will be equal when its displacement is :
(amplitude = a) :

Options

A. `(a)/(2)`
B. `(a)/(sqrt(2))`
C. `a sqrt(2)`
D. `(a sqrt(2))/(3)`

Answer

B

Explanation

K.E. = P.E.
`(1)/(2)m omega^(2)(r^(2)-y^(2))=(1)/(2)m omega^(2)y^(2)`.
`implies" "y=( r )/(sqrt(2))=(a)/(sqrt(2))`.
So correct choice is (b).