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The motion of 10 g mass tied to massless...

The motion of 10 g mass tied to massless spring is represented by S.H.M. `x=25cos(3t+(pi)/(4))` where x is in cm and t in second, the force constant of the spring is :

A

`9" N m"^(-1)`

B

`0.9" N m"^(-1)`

C

`0.09" N m"^(-1)`

D

none of the above.

Text Solution

Verified by Experts

The correct Answer is:
C

Here `omega t=3t`
`implies" "omega=3` rad/s.
Now `" "v=(1)/(2pi)sqrt((k)/(m))`
or `" "omega=sqrt((k)/(m))`
`implies" "k=omega^(2)m`
`:." "k=9xx(10)/(1000)=0.09"N"//"m"`.
So the correct choice is ( c ).
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