The potential energy of particle moving is S.H.M. is `(1)/(2)kx^(2)`. If the frequency of the particle is n, the frequency of oscillation of P.E. is :

Options

A. n
B. 2n
C. `(n)/(2)`
D. `n sqrt(2)`.

Answer

B

Explanation

Here `x=r sin omegat`.
and P.E. `=(1)/(2)kx^(2)=(1)/(2)m omega^(2)x" "{because k=m omega^(2)}`
P.E. `=(1)/(2)m omega^(2).r^(2)sin^(2)omegat`
P.E. `=(1)/(2)m omega^(2)r^(2)[(1-cos 2omegat)/(2)]`
`:.` Therefore, frequency of P.E. is `2omega` i.e., twice the frequency of particle `(omega)`.
Hence correct choice is (b).