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If the length of second's pendulum is in...

If the length of second's pendulum is increased by 2%, how many seconds it loses per day ?

A

3927 s

B

1728 s

C

3427 s

D

864 s.

Text Solution

Verified by Experts

The correct Answer is:
D
`T=2pi sqrt(l//g)` and `T.=2pi sqrt((102l)/(100g))`
`:." "(T.)/(T)=sqrt((102)/(100))impliesT.=2[1+(2)/(100)]^(1//2)`
or `" "T.=2[1+(1)/(100)]=2+(2)/(100)`
Loss in time `=2+(2)/(100)-2=(2)/(100)` s.
`:.` Loss in time for 2 s `=(2)/(100)`
Loss in time for day `=(2)/(100)xx(86400)/(2)=864` s.
Hence correct choice is (d).
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