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Two pendulums have time periods T and (...

Two pendulums have time periods T and `(5T)/(4)`. They start swinging in S.H.M. together. What will be the phase difference between them after the longer has completed one oscillation ?

A

`45^(@)`

B

`90^(@)`

C

`60^(@)`

D

`30^(@)`

Text Solution

Verified by Experts

The correct Answer is:
B
No. of vibrations completed by shorter pendulum during the time bigger pendulum completes one vibration is `n=((5T)/(4))/(T)=(5)/(4)`
`:.` Diff. in vibrations `=(5)/(4)-1=(1)/(4)`.
`:.` Phase difference `=(1)/(4)xx2pi=(pi)/(2)=90^(@)`.
Thus correct choice is (b).
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