A particle executes S.H.M. with amplitude 2 cm. At extreme position the force is 4 N. The force acting on it at a position mid-way between the mean and extreme is :

Options

A. 1 N
B. 2 N
C. 3 N
D. 4 N

Answer

B

Explanation

`a=omega^(2)y`.
`:." "F=ma=m omega^(2)y`.
`implies" "F prop y`.
Thus when displacement is halved, then force also becomes half i.e., `(1)/(2)(4)=2N`.
Hence correct choice is (b).