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The maximum speed of a particle executin...

The maximum speed of a particle executing an S.H.M. is `1" m s"^(-1)` and maximum acceleration is `1.57" m s"^(-2)`. The time period of S.H.M. is :

A

0.25 s

B

4.00 s

C

1.57 s

D

`(1)/(1.57)s.`

Text Solution

Verified by Experts

The correct Answer is:
B
`v_("max")=r omega` and `a_("max")=omega^(2)r`.
`(a_("max"))/(v_("max"))=omega=(2pi)/(T)`
`T=2pi""(v_("max"))/(a_("max"))=2pi.(1)/(157)=4` s.
Hence correct choice is (b).
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