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For a particle executing simple harmonic...

For a particle executing simple harmonic motion, the kinetic energy K is given by,
`K=K_(0)cos^(2)omegat`
The maximum value of potential energy is :

A

`K_(0)`

B

`zero`

C

`K_(0)//2`

D

not obtainable

Text Solution

Verified by Experts

The correct Answer is:
A
At the extreme the whole energy is potential when `cos omegat.=1`
`:. U=K_(0)xx1=K_(0)`.
Correct choice is (a).
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