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The bob of simple pendulum of length L ...

The bob of simple pendulum of length L is released at time t = 0 from a position of small angular displacement `theta`. Its linear displacement at time t is given by :

A

`x=thetao sin 2pi sqrt((L)/(g))xxt`

B

`x=L thetao cos 2pi sqrt((g)/(L))xxt`

C

`x=L thetao sin sqrt((g)/(L))xx t`

D

`x=L thetao cos sqrt((g)/(L))xxt`.

Text Solution

Verified by Experts

The correct Answer is:
D
Here displacement is given by x = A `cos omegat` when A is linear amplitude.
Now `" "theta=(A)/(L)` (when `theta` is small)
or `" "A=L theta`
Also `" "omega=(2pi)/(T)=(2pi)/(2pi sqrt((L)/(g)))=sqrt((g)/(L))`
`:." "x=L theta cos sqrt((g)/(L)).t.`
Correct choice is (d).
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